8j^2-2j-8=0

Solution for 8j^2-2j-8=0 equation:

8j^2-2j-8=0

a = 8; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·8·(-8)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$
$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{65}}{2*8}=\frac{2-2\sqrt{65}}{16}
$
$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{65}}{2*8}=\frac{2+2\sqrt{65}}{16}
$